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[filmscanners] RE: Terminology


  • To: lexa@lexa.ru
  • Subject: [filmscanners] RE: Terminology
  • From: "Kapetanakis, Constantine" <KAPETAC@polaroid.com>
  • Date: Wed, 8 May 2002 08:20:44 -0400
  • Unsubscribe: mailto:listserver@halftone.co.uk

That's not true. The computer stores information using the concept of bits
and words. Each bit is either a 0 or 1 and each byte contains 8 bits.
If the scanner (or any other electronic imaging system) outputs 8 bits then
you only need one byte to store the data. However if the system outputs
anything higher than 8 bits but less than 16,  then you need two bytes. So
whether your system outputs 12 or 14 your storage requirements are the same.
Both will be stored as 16 bit (2 byte) images.


-----Original Message-----
From: Neville Skinner [mailto:nevilles@senet.com.au]
Sent: Tuesday, May 07, 2002 9:07 AM
To: KAPETAC@polaroid.com
Subject: [filmscanners] Re: Terminology


At 08:52 7/05/02 -0400, Constantine wrote:
>That's correct. 48 bits is 16 x 3 (for RGB). However, i don't know of any
>desktop scanner that gives you 16 bits per color. The Niko 4000ED, Polaroid
>Sprintscan 4000+, SS45 Ultra SS120 all give you 14 bits ........



Just a guess, but 14 bits = 2 lots of 7 bits (heavy huh?).

This leaves the 8th bit for parity/error checking.
Dunno, but just a thought


Kindest regards,
Neville Skinner.

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