[filmscanners] Re: Possible two-pass trick on the Minolta Multi-ScanPro?

["Ng Hun Yang" <nhyone@singnet.com.sg>]

EdHamrick@aol.com wrote:
> I didn't test it, but I suspect a divisor of 1 will work fine.
> However, I'm not convinced that this would be at all useful.

Here's what I have in mind.

Assuming the resolving power is only 4800 dpi, so even if we
offset by 1 step, we won't have two discrete samples.

But, assuming the pixel structure at 9600 dpi looks like this:

    abcdefghij

First pass, we read: ab cd ef gh ij
Second pass, we read: a bc de fg hi j

I assume that the CCD will pick up the average, so for pixels a
and b, we actually read a value of a + b.

Since we can control where to start to read, we start off beyond
the edge, where a = 0 (or some fixed known value). Once we know a,
we can know b, and so on.

Will this work? :-)


(void *) &NHY;

*  That's all, folks!  *

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